Adding Days To $Date In PHP

Answer :

All you have to do is use days instead of day like this:

<?php $Date = "2010-09-17"; echo date('Y-m-d', strtotime($Date. ' + 1 days')); echo date('Y-m-d', strtotime($Date. ' + 2 days')); ?> 

And it outputs correctly:

2010-09-18 2010-09-19 

If you're using PHP 5.3, you can use a DateTime object and its add method:

$Date1 = '2010-09-17'; $date = new DateTime($Date1); $date->add(new DateInterval('P1D')); // P1D means a period of 1 day $Date2 = $date->format('Y-m-d'); 

Take a look at the DateInterval constructor manual page to see how to construct other periods to add to your date (2 days would be 'P2D', 3 would be 'P3D', and so on).

Without PHP 5.3, you should be able to use strtotime the way you did it (I've tested it and it works in both 5.1.6 and 5.2.10):

$Date1 = '2010-09-17'; $Date2 = date('Y-m-d', strtotime($Date1 . " + 1 day")); // var_dump($Date2) returns "2010-09-18" 

From PHP 5.2 on you can use modify with a DateTime object:

http://php.net/manual/en/datetime.modify.php

$Date1 = '2010-09-17'; $date = new DateTime($Date1); $date->modify('+1 day'); $Date2 = $date->format('Y-m-d'); 

Be careful when adding months... (and to a lesser extent, years)